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Measurement of the high resistance by using loss of charge method.

Aim:- Measurement of the high resistance by using loss of charge method.
Apparatus:- Multimeter –1no
Voltmeter –(0-30v)-1no
Power supply-(0-30v)-1no
Circuit Diagram:-
Observation Table:-
Time (sec) V(without
V(with R) Log10(V/v)
without R
with R
In this method the resistance which is measured is connected in parallel with
the capacitor C and the electronic voltmeter V. The capacitor is the charged up to some
suitable voltage by means of the battery having the voltage V and is then allowed to
discharge through the resistance.
The terminal voltage is observed over the considerable period of the time
during discharge.
Let ,
V=initial voltage on the charged capacitor .
.v=instantaneous discharging voltage.
I=the discharging capacitor current through the unknown resistor at time “t”.
Q=the charge still remaining in the capacitor.
I=dq/dt=-cdv/dt since[I=V/R]
V/R+C dv/dt=0 (1)
1/RC dt+1/V.dV=0
integrating both sides
t/RC+logev+K=0 (2)
K is const. of integration
At initial condition
When T=0 , v=V from equ. (2)
now equ. (2) becomes
therefore. Loge (v/V)=-t/RC
Taking log on both sides
1) Connections is make as per the circuit diagram.
2) Close the switch s and keep s2 open the capacitor charge by own leakage method.
3) New open reading and voltmeter .as its own resistance.
4) Note down the reading of the voltmeter Vs equal interval of the time
Result:- High resistance of the resistance is calculated by using loss of charge method.
Viva Questions:- 1)Why this method is called as loss of charge method?
2)What errors occur while performing this practical?


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